Find Largest Element of an Array using C++

This program takes n number of element from user(where, n is specified by user) and stores data in an array. Then, this program displays the largest element of that array using loops.

Source Code to Display Largest Element of an array

#include <iostream>
using namespace std;
int main(){
    int i,n;
    float arr[100];
    cout << "Enter total number of elements: ";
    cin >> n;
    cout << endl;
    while (n>100 || n<=0)
    {
        cout << "Error! number should in range of (1 to 100)." << endl;
        cout << "Enter the number again: ";
        cin >> n;
    }
    for(i=0;i<n;++i)  /* Stores number entered by user. */
    {
       cout << "Enter Number " << i+1 << " : ";
       cin >> arr[i];
    }
    for(i=1;i<n;++i)  /* Loop to store largest number to arr[0] */
    {
       if(arr[0]<arr[i]) /* Change < to > if you want to find smallest element*/
           arr[0]=arr[i];
    }
    cout << "Largest element = " << arr[0];
    return 0;
}

Output

Enter total number of elements: 8

Enter Number 1: 23.4
Enter Number 2: -34.5
Enter Number 3: 50
Enter Number 4: 33.5
Enter Number 5: 55.5
Enter Number 6: 43.7
Enter Number 7: 5.7
Enter Number 8: -66.5

Largest element = 55.5

This program takes n number of elements from user and stores it in array arr[]. To find the largest element, the first two elements of array are checked and largest of these two element is placed in arr[0]. Then, the first and third elements are checked and largest of these two element is placed in arr[0]. This process continues until and first and last elements are checked. After this process, the largest element of an array will be in arr[0] position.